15b^2+26b-10=-18

Solution for 15b^2+26b-10=-18 equation:

15b^2+26b-10=-18

We move all terms to the left:

15b^2+26b-10-(-18)=0

We add all the numbers together, and all the variables

15b^2+26b+8=0

a = 15; b = 26; c = +8;
Δ = b2-4ac
Δ = 262-4·15·8
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-14}{2*15}=\frac{-40}{30}
=-1+1/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+14}{2*15}=\frac{-12}{30}
=-2/5
$